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Update findoidjoins for 6.5: remove workaround for long-dead bug,
use NOT EXISTS() which is a lot faster than NOT IN (), update documentation.
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@ -4,7 +4,7 @@
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#
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PGINTERFACE = ../pginterface/pginterface.o ../pginterface/halt.o # these have to be in your library search path
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TARGET = findoidjoins
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CFLAGS = -g -Wall -I. -I../../src/interfaces/libpq -I/usr/local/pgsql/include
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CFLAGS = -g -Wall -I. -I../pginterface -I../../src/interfaces/libpq -I/usr/local/pgsql/include
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LDFLAGS = -L/usr/local/pgsql/lib -lpq
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all : $(TARGET)
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@ -1,27 +1,36 @@
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findoidjoins
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This program scans the a database, and prints oid fields, and the tables
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they join to. PostgreSQL version 6.3.2 crashes with aggregates on
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views, so I have removed the view pg_user from the list of relations to
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examine.
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This program scans a database, and prints oid fields and the tables
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they join to. CAUTION: it is ver-r-r-y slow on a large database, or
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even a not-so-large one. We don't really recommend running it on
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anything but an empty database.
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It requires /pgsql/contrib/pginterface to be compiled first.
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It requires pgsql/contrib/pginterface to be compiled first.
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Run on am empty database, it returns the system join relationships:
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Run on an empty database, it returns the system join relationships
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(shown below for 6.5). Note that unexpected matches may indicate
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bogus entries in system tables --- don't accept a peculiar match
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without question. In particular, a field shown as joining to more
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than one target table is probably messed up.
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The shell script make_oidjoins_check converts findoidjoins' output
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into an SQL script that checks for dangling links (entries in an
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OID column that don't match any row in the expected table).
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The result of this script should be installed as the "oidjoins"
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regression test. The oidjoins test should be updated after any
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revision in the patterns of cross-links between system tables.
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(Ideally we'd just regenerate the script as part of the regression
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tests themselves, but that seems too slow...)
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---------------------------------------------------------------------------
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Join pg_aggregate.aggtransfn1 => pg_proc.oid
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Join pg_aggregate.aggtransfn2 => pg_proc.oid
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Join pg_aggregate.aggfinalfn => pg_proc.oid
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Join pg_aggregate.aggbasetype => pg_proc.oid
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Join pg_aggregate.aggbasetype => pg_type.oid
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Join pg_aggregate.aggtranstype1 => pg_proc.oid
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Join pg_aggregate.aggtranstype1 => pg_type.oid
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Join pg_aggregate.aggtranstype2 => pg_type.oid
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Join pg_aggregate.aggfinaltype => pg_proc.oid
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Join pg_aggregate.aggfinaltype => pg_type.oid
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Join pg_am.amgettuple => pg_proc.oid
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Join pg_am.aminsert => pg_proc.oid
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@ -35,14 +44,10 @@ Join pg_am.ambuild => pg_proc.oid
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Join pg_amop.amopid => pg_am.oid
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Join pg_amop.amopclaid => pg_opclass.oid
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Join pg_amop.amopopr => pg_operator.oid
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Join pg_amop.amopopr => pg_proc.oid
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Join pg_amop.amopselect => pg_proc.oid
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Join pg_amop.amopnpages => pg_proc.oid
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Join pg_amproc.amid => pg_am.oid
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Join pg_amproc.amopclaid => pg_opclass.oid
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Join pg_amproc.amopclaid => pg_operator.oid
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Join pg_amproc.amopclaid => pg_proc.oid
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Join pg_amproc.amproc => pg_operator.oid
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Join pg_amproc.amproc => pg_proc.oid
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Join pg_attribute.attrelid => pg_class.oid
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Join pg_attribute.atttypid => pg_type.oid
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@ -70,15 +75,12 @@ Join pg_proc.prolang => pg_language.oid
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Join pg_proc.prorettype => pg_type.oid
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Join pg_rewrite.ev_class => pg_class.oid
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Join pg_type.typrelid => pg_class.oid
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Join pg_type.typelem => pg_operator.oid
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Join pg_type.typelem => pg_proc.oid
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Join pg_type.typelem => pg_type.oid
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Join pg_type.typinput => pg_proc.oid
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Join pg_type.typoutput => pg_proc.oid
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Join pg_type.typreceive => pg_proc.oid
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Join pg_type.typsend => pg_proc.oid
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---------------------------------------------------------------------------
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Bruce Momjian (root@candle.pha.pa.us)
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@ -50,8 +50,7 @@ main(int argc, char **argv)
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SELECT relname \
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FROM pg_class c \
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WHERE relkind = 'r' AND \
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relhasrules = 'f' AND \
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relname != 'pg_user' \
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relhasrules = 'f' \
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ORDER BY 1; \
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");
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doquery("FETCH ALL IN c_relations");
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@ -1,17 +1,37 @@
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:
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#! /bin/sh
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# You first run findoidjoins on the template1 database, and send that
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# output into this file to generate a list of SQL statements.
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# NOTE: any field that findoidjoins thinks joins to more than one table
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# will NOT be checked by the output of this script. You should be
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# suspicious of multiple entries in findoidjoins' output.
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# Caution: you may need to use GNU awk.
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AWK=${AWK:-awk}
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trap "rm -f /tmp/$$ /tmp/$$a /tmp/$$b" 0 1 2 3 15
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# Read input
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cat "$@" >/tmp/$$
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# Look for fields with multiple references.
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cat /tmp/$$ | cut -d' ' -f2 | sort | uniq -d >/tmp/$$a
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if [ -s /tmp/$$a ] ; then
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echo "Ignoring these fields that link to multiple tables:" 1>&2
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cat /tmp/$$a 1>&2
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fi
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# Get the non-multiply-referenced fields.
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cat /tmp/$$ | while read LINE
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do
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set -- $LINE
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grep "$2" /tmp/$$a >/dev/null 2>&1 || echo $LINE
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done >/tmp/$$b
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# Generate the output.
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cat /tmp/$$b |
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awk -F'[ \.]' '\
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$AWK -F'[ \.]' '\
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BEGIN \
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{
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printf "\
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@ -23,13 +43,11 @@ awk -F'[ \.]' '\
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printf "\
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SELECT oid, %s.%s \n\
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FROM %s \n\
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WHERE %s%s.%s%s NOT IN (SELECT oid FROM %s) AND \n\
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%s%s.%s%s != 0;\n", $2, $3, $2,
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($5 == "pg_proc") ? "RegprocToOid(" : "",
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$2, $3,
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($5 == "pg_proc") ? ")" : "",
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$5,
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($5 == "pg_proc") ? "RegprocToOid(" : "",
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$2, $3,
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($5 == "pg_proc") ? ")" : "";
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WHERE %s.%s != 0 AND \n\
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NOT EXISTS(SELECT * FROM %s AS t1 WHERE t1.oid = %s.%s);\n",
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$2, $3, $2,
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$2, $3,
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$5, $2, $3;
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}'
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exit 0
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