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Ensure that snprintf.c's fmtint() doesn't overflow when printing INT64_MIN.

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This isn't actually a live bug, as the output happens to be the
same.  But it upsets tools like UBSan, which makes it worthwhile to
fix.

As it's an issue without practical consequences, don't backpatch.

Author: Andres Freund
Discussion: https://postgr.es/m/20180928001121.hhx5n6dsygqxr5wu@alap3.anarazel.de
This commit is contained in:
Andres Freund 2018-10-03 13:02:25 -07:00
parent 9a3cebeaa7
commit 4868e44685
1 changed files with 4 additions and 3 deletions
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7
src/port/snprintf.c
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@ -1007,6 +1007,7 @@ fmtint(long long value, char type, int forcesign, int leftjust,
PrintfTarget *target)
{
unsigned long long base;
unsigned long long uvalue;
int dosign;
const char *cvt = "0123456789abcdef";
int signvalue = 0;
@ -1045,7 +1046,9 @@ fmtint(long long value, char type, int forcesign, int leftjust,
/* Handle +/- */
if (dosign && adjust_sign((value < 0), forcesign, &signvalue))
value = -value;
uvalue = -(uint64) value;
else
uvalue = (uint64) value;
/*
* SUS: the result of converting 0 with an explicit precision of 0 is no
@ -1056,8 +1059,6 @@ fmtint(long long value, char type, int forcesign, int leftjust,
else
{
/* make integer string */
unsigned long long uvalue = (unsigned long long) value;
do
{
convert[sizeof(convert) - (++vallen)] = cvt[uvalue % base];