postgresql/contrib/pgcrypto/crypt-md5.c

/*
 * File imported from FreeBSD, original by Poul-Henning Kamp.
 *
 * $FreeBSD: src/lib/libcrypt/crypt-md5.c,v 1.5 1999/12/17 20:21:45 peter Exp $
 *
 * $PostgreSQL: pgsql/contrib/pgcrypto/crypt-md5.c,v 1.8.2.1 2009/04/15 18:58:32 mha Exp $
 */

#include "postgres.h"

#include "px.h"
#include "px-crypt.h"

#define MD5_SIZE 16

static const char _crypt_a64[] =
"./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";

static void
_crypt_to64(char *s, unsigned long v, int n)
{
	while (--n >= 0)
	{
		*s++ = _crypt_a64[v & 0x3f];
		v >>= 6;
	}
}

/*
 * UNIX password
 */

char *
px_crypt_md5(const char *pw, const char *salt, char *passwd, unsigned dstlen)
{
	static char *magic = "$1$"; /* This string is magic for this algorithm.
								 * Having it this way, we can get get better
								 * later on */
	static char *p;
	static const char *sp,
			   *ep;
	unsigned char final[MD5_SIZE];
	int			sl,
				pl,
				i;
	PX_MD	   *ctx,
			   *ctx1;
	int			err;
	unsigned long l;

	if (!passwd || dstlen < 120)
		return NULL;

	/* Refine the Salt first */
	sp = salt;

	/* If it starts with the magic string, then skip that */
	if (!strncmp(sp, magic, strlen(magic)))
		sp += strlen(magic);

	/* It stops at the first '$', max 8 chars */
	for (ep = sp; *ep && *ep != '$' && ep < (sp + 8); ep++)
		continue;

	/* get the length of the true salt */
	sl = ep - sp;

	/* */
	err = px_find_digest("md5", &ctx);
	if (err)
		return NULL;
	err = px_find_digest("md5", &ctx1);

	/* The password first, since that is what is most unknown */
	px_md_update(ctx, (uint8 *) pw, strlen(pw));

	/* Then our magic string */
	px_md_update(ctx, (uint8 *) magic, strlen(magic));

	/* Then the raw salt */
	px_md_update(ctx, (uint8 *) sp, sl);

	/* Then just as many characters of the MD5(pw,salt,pw) */
	px_md_update(ctx1, (uint8 *) pw, strlen(pw));
	px_md_update(ctx1, (uint8 *) sp, sl);
	px_md_update(ctx1, (uint8 *) pw, strlen(pw));
	px_md_finish(ctx1, final);
	for (pl = strlen(pw); pl > 0; pl -= MD5_SIZE)
		px_md_update(ctx, final, pl > MD5_SIZE ? MD5_SIZE : pl);

	/* Don't leave anything around in vm they could use. */
	memset(final, 0, sizeof final);

	/* Then something really weird... */
	for (i = strlen(pw); i; i >>= 1)
		if (i & 1)
			px_md_update(ctx, final, 1);
		else
			px_md_update(ctx, (uint8 *) pw, 1);

	/* Now make the output string */
	strcpy(passwd, magic);
	strncat(passwd, sp, sl);
	strcat(passwd, "$");

	px_md_finish(ctx, final);

	/*
	 * and now, just to make sure things don't run too fast On a 60 Mhz
	 * Pentium this takes 34 msec, so you would need 30 seconds to build a
	 * 1000 entry dictionary...
	 */
	for (i = 0; i < 1000; i++)
	{
		px_md_reset(ctx1);
		if (i & 1)
			px_md_update(ctx1, (uint8 *) pw, strlen(pw));
		else
			px_md_update(ctx1, final, MD5_SIZE);

		if (i % 3)
			px_md_update(ctx1, (uint8 *) sp, sl);

		if (i % 7)
			px_md_update(ctx1, (uint8 *) pw, strlen(pw));

		if (i & 1)
			px_md_update(ctx1, final, MD5_SIZE);
		else
			px_md_update(ctx1, (uint8 *) pw, strlen(pw));
		px_md_finish(ctx1, final);
	}

	p = passwd + strlen(passwd);

	l = (final[0] << 16) | (final[6] << 8) | final[12];
	_crypt_to64(p, l, 4);
	p += 4;
	l = (final[1] << 16) | (final[7] << 8) | final[13];
	_crypt_to64(p, l, 4);
	p += 4;
	l = (final[2] << 16) | (final[8] << 8) | final[14];
	_crypt_to64(p, l, 4);
	p += 4;
	l = (final[3] << 16) | (final[9] << 8) | final[15];
	_crypt_to64(p, l, 4);
	p += 4;
	l = (final[4] << 16) | (final[10] << 8) | final[5];
	_crypt_to64(p, l, 4);
	p += 4;
	l = final[11];
	_crypt_to64(p, l, 2);
	p += 2;
	*p = '\0';

	/* Don't leave anything around in vm they could use. */
	memset(final, 0, sizeof final);

	px_md_free(ctx1);
	px_md_free(ctx);

	return passwd;
}