rand uniform: add comments outlining the algorithm

Reviewed-by: Tom Cosgrove <tom.cosgrove@arm.com>
Reviewed-by: Matthias St. Pierre <Matthias.St.Pierre@ncp-e.com>
Reviewed-by: Tomas Mraz <tomas@openssl.org>
(Merged from https://github.com/openssl/openssl/pull/22499)
This commit is contained in:
Pauli 2023-11-01 08:52:00 +11:00 committed by Tomas Mraz
parent d05e0e40d7
commit dfb26e03c2

View File

@ -12,7 +12,14 @@
/*
* Implementation an optimal random integer in a range function.
* Refer: https://github.com/apple/swift/pull/39143 for a description
*
* Essentially it boils down to incrementally generating a fixed point
* number on the interval [0, 1) and multiplying this number by the upper
* range limit. Once it is certain what the fractional part contributes to
* the integral part of the product, the algorithm has produced a definitive
* result.
*
* Refer: https://github.com/apple/swift/pull/39143 for a fuller description
* of the algorithm.
*/
uint32_t ossl_rand_uniform_uint32(OSSL_LIB_CTX *ctx, uint32_t upper, int *err)
@ -29,17 +36,43 @@ uint32_t ossl_rand_uniform_uint32(OSSL_LIB_CTX *ctx, uint32_t upper, int *err)
}
if (unlikely(upper == 1))
return 0;
/* Get 32 bits of entropy */
if (RAND_bytes_ex(ctx, (unsigned char *)&rand, sizeof(rand), 0) <= 0) {
*err = 1;
return 0;
}
/*
* We are generating a fixed point number on the interval [0, 1).
* Multiplying this by the range gives us a number on [0, upper).
* The high word of the multiplication result represents the integral
* part we want. The lower word is the fractional part. We can early exit if
* if the fractional part is small enough that no carry from the next lower
* word can cause an overflow and carry into the integer part. This
* happens when the fractional part is bounded by 2^32 - upper which
* can be simplified to just -upper (as an unsigned integer).
*/
prod = (uint64_t)upper * rand;
i = prod >> 32;
f = prod & 0xffffffff;
if (likely(f <= 1 + ~upper)) /* 1+~upper == -upper but compilers whine */
return i;
/*
* We're in the position where the carry from the next word *might* cause
* a carry to the integral part. The process here is to generate the next
* word, multiply it by the range and add that to the current word. If
* it overflows, the carry propagates to the integer part (return i+1).
* If it can no longer overflow regardless of further lower order bits,
* we are done (return i). If there is still a chance of overflow, we
* repeat the process with the next lower word.
*
* Each *bit* of randomness has a probability of one half of terminating
* this process, so each each word beyond the first has a probability
* of 2^-32 of not terminating the process. That is, we're extremely
* likely to stop very rapidly.
*/
for (j = 0; j < max_followup_iterations; j++) {
if (RAND_bytes_ex(ctx, (unsigned char *)&rand, sizeof(rand), 0) <= 0) {
*err = 1;
@ -59,8 +92,8 @@ uint32_t ossl_rand_uniform_uint32(OSSL_LIB_CTX *ctx, uint32_t upper, int *err)
}
/*
* If we get here, we've consumed 32 * max_followup_iterations + 32 bits
* with no firm decision, this gives a bias with probability < 2^(32*n),
* likely acceptable.
* with no firm decision, this gives a bias with probability < 2^-(32*n),
* which is likely acceptable.
*/
return i;
}