bn/bn_div.c: make conditional addition unconditional

and add template for constant-time bn_div_3_words.

Reviewed-by: Paul Dale <paul.dale@oracle.com>
Reviewed-by: Matt Caswell <matt@openssl.org>
(Merged from https://github.com/openssl/openssl/pull/7589)
This commit is contained in:
Andy Polyakov 2018-11-07 22:18:33 +01:00 committed by Matt Caswell
parent 31703da3b8
commit 3da2e9c4ee

View File

@ -86,6 +86,57 @@ int BN_div(BIGNUM *dv, BIGNUM *rem, const BIGNUM *m, const BIGNUM *d,
#else #else
# if defined(BN_DIV3W)
BN_ULONG bn_div_3_words(const BN_ULONG *m, BN_ULONG d1, BN_ULONG d0);
# elif 0
/*
* This is #if-ed away, because it's a reference for assembly implementations,
* where it can and should be made constant-time. But if you want to test it,
* just replace 0 with 1.
*/
# if BN_BITS2 == 64 && defined(__SIZEOF_INT128__) && __SIZEOF_INT128__==16
# undef BN_ULLONG
# define BN_ULLONG __uint128_t
# define BN_LLONG
# endif
# ifdef BN_LLONG
# define BN_DIV3W
/*
* Interface is somewhat quirky, |m| is pointer to most significant limb,
* and less significant limb is referred at |m[-1]|. This means that caller
* is responsible for ensuring that |m[-1]| is valid. Second condition that
* has to be met is that |d0|'s most significant bit has to be set. Or in
* other words divisor has to be "bit-aligned to the left." bn_div_fixed_top
* does all this. The subroutine considers four limbs, two of which are
* "overlapping," hence the name...
*/
static BN_ULONG bn_div_3_words(const BN_ULONG *m, BN_ULONG d1, BN_ULONG d0)
{
BN_ULLONG R = ((BN_ULLONG)m[0] << BN_BITS2) | m[-1];
BN_ULLONG D = ((BN_ULLONG)d0 << BN_BITS2) | d1;
BN_ULONG Q = 0, mask;
int i;
for (i = 0; i < BN_BITS2; i++) {
Q <<= 1;
if (R >= D) {
Q |= 1;
R -= D;
}
D >>= 1;
}
mask = 0 - (Q >> (BN_BITS2 - 1)); /* does it overflow? */
Q <<= 1;
Q |= (R >= D);
return (Q | mask) & BN_MASK2;
}
# endif
# endif
# if !defined(OPENSSL_NO_ASM) && !defined(OPENSSL_NO_INLINE_ASM) \ # if !defined(OPENSSL_NO_ASM) && !defined(OPENSSL_NO_INLINE_ASM) \
&& !defined(PEDANTIC) && !defined(BN_DIV3W) && !defined(PEDANTIC) && !defined(BN_DIV3W)
# if defined(__GNUC__) && __GNUC__>=2 # if defined(__GNUC__) && __GNUC__>=2
@ -137,7 +188,7 @@ int BN_div(BIGNUM *dv, BIGNUM *rem, const BIGNUM *m, const BIGNUM *d,
int BN_div(BIGNUM *dv, BIGNUM *rm, const BIGNUM *num, const BIGNUM *divisor, int BN_div(BIGNUM *dv, BIGNUM *rm, const BIGNUM *num, const BIGNUM *divisor,
BN_CTX *ctx) BN_CTX *ctx)
{ {
int norm_shift, i, loop; int norm_shift, i, j, loop;
BIGNUM *tmp, wnum, *snum, *sdiv, *res; BIGNUM *tmp, wnum, *snum, *sdiv, *res;
BN_ULONG *resp, *wnump; BN_ULONG *resp, *wnump;
BN_ULONG d0, d1; BN_ULONG d0, d1;
@ -291,8 +342,7 @@ int BN_div(BIGNUM *dv, BIGNUM *rm, const BIGNUM *num, const BIGNUM *divisor,
* the first part of the loop uses the top two words of snum and sdiv * the first part of the loop uses the top two words of snum and sdiv
* to calculate a BN_ULONG q such that | wnum - sdiv * q | < sdiv * to calculate a BN_ULONG q such that | wnum - sdiv * q | < sdiv
*/ */
# if defined(BN_DIV3W) && !defined(OPENSSL_NO_ASM) # if defined(BN_DIV3W)
BN_ULONG bn_div_3_words(BN_ULONG *, BN_ULONG, BN_ULONG);
q = bn_div_3_words(wnump, d1, d0); q = bn_div_3_words(wnump, d1, d0);
# else # else
BN_ULONG n0, n1, rem = 0; BN_ULONG n0, n1, rem = 0;
@ -376,20 +426,22 @@ int BN_div(BIGNUM *dv, BIGNUM *rm, const BIGNUM *num, const BIGNUM *divisor,
* ingore top values of the bignums just sub the two BN_ULONG arrays * ingore top values of the bignums just sub the two BN_ULONG arrays
* with bn_sub_words * with bn_sub_words
*/ */
if (bn_sub_words(wnum.d, wnum.d, tmp->d, div_n + 1)) { l0 = bn_sub_words(wnum.d, wnum.d, tmp->d, div_n + 1);
/* q -= l0;
* Note: As we have considered only the leading two BN_ULONGs in /*
* the calculation of q, sdiv * q might be greater than wnum (but * Note: As we have considered only the leading two BN_ULONGs in
* then (q-1) * sdiv is less or equal than wnum) * the calculation of q, sdiv * q might be greater than wnum (but
*/ * then (q-1) * sdiv is less or equal than wnum)
q--; */
if (bn_add_words(wnum.d, wnum.d, sdiv->d, div_n)) for (l0 = 0 - l0, j = 0; j < div_n; j++)
/* tmp->d[j] = sdiv->d[j] & l0;
* we can't have an overflow here (assuming that q != 0, but l0 = bn_add_words(wnum.d, wnum.d, tmp->d, div_n);
* if q == 0 then tmp is zero anyway) /*
*/ * we can't have an overflow here (assuming that q != 0, but
(*wnump)++; * if q == 0 then tmp is zero anyway)
} */
(*wnump) += l0;
/* store part of the result */ /* store part of the result */
resp--; resp--;
*resp = q; *resp = q;