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Abdelilah Essiari <aes@george.lbl.gov> reports that for very small

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records, EVP_EncodeUpdate() may misbehave.  This happens when there's
a record boundary between the two ending b64 equal signs, which makes
EVP_EncodeUpdate think there has been more than one EOF, and therefore
add an extra NUL at the end of the output buffer.  This fix corrects
that problem.
This commit is contained in:
Richard Levitte 2000-08-11 08:36:25 +00:00
parent 15c2e1260b
commit 35140f3354
1 changed files with 10 additions and 0 deletions
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10
crypto/evp/encode.c
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@ -292,7 +292,17 @@ int EVP_DecodeUpdate(EVP_ENCODE_CTX *ctx, unsigned char *out, int *outl,
/* If we are at the end of input and it looks like a
* line, process it. */
if (((i+1) == inl) && (((n&3) == 0) || eof))
{
v=B64_EOF;
/* In case things were given us in really small
records (so two '=' were given in separate
updates), eof may contain the incorrect number
of ending bytes to skip, so let's redo the count */
eof = 0;
if (d[n-1] == '=') eof++;
if (d[n-2] == '=') eof++;
/* There will never be more than two '=' */
}
if ((v == B64_EOF) || (n >= 64))
{