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printf("%d", <size_t>) is invalid. As this is for legacy compilers, don't rely on %zu but rather cast to unsigned long long. Signed-off-by: H. Peter Anvin (Intel) <hpa@zytor.com>
47 lines
990 B
C
47 lines
990 B
C
/*
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* vsnprintf()
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*
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* Poor substitute for a real vsnprintf() function for systems
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* that don't have them...
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*/
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#include "compiler.h"
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#include "nasmlib.h"
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#include "error.h"
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#if !defined(HAVE_VSNPRINTF) && !defined(HAVE__VSNPRINTF)
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#define BUFFER_SIZE 65536 /* Bigger than any string we might print... */
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static char snprintf_buffer[BUFFER_SIZE];
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int vsnprintf(char *str, size_t size, const char *format, va_list ap)
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{
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int rv, bytes;
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if (size > BUFFER_SIZE) {
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nasm_panic("vsnprintf: size (%llu) > BUFFER_SIZE (%d)",
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(unsigned long long)size, BUFFER_SIZE);
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size = BUFFER_SIZE;
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}
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rv = vsprintf(snprintf_buffer, format, ap);
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if (rv >= BUFFER_SIZE)
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nasm_panic("vsnprintf buffer overflow");
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if (size > 0) {
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if ((size_t)rv < size-1)
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bytes = rv;
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else
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bytes = size-1;
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memcpy(str, snprintf_buffer, bytes);
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str[bytes] = '\0';
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}
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return rv;
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}
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#endif
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