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68e3802b23
Sometimes we want to search for an exact key only, and reject the case when tree->key < key. Add rb_search_exact() for this purpose, rather than forcing the caller to perform the comparison in open code. Signed-off-by: H. Peter Anvin (Intel) <hpa@zytor.com>
260 lines
7.8 KiB
C
260 lines
7.8 KiB
C
/* ----------------------------------------------------------------------- *
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*
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* Copyright 1996-2020 The NASM Authors - All Rights Reserved
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* See the file AUTHORS included with the NASM distribution for
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* the specific copyright holders.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following
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* conditions are met:
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*
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* * Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* * Redistributions in binary form must reproduce the above
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* copyright notice, this list of conditions and the following
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* disclaimer in the documentation and/or other materials provided
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* with the distribution.
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*
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* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND
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* CONTRIBUTORS "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES,
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* INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF
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* MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
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* DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR
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* CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
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* SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
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* NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES;
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* LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN
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* CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR
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* OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE,
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* EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
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*
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* ----------------------------------------------------------------------- */
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/*
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* rbtree.c
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*
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* Simple implementation of a "left-leaning threaded red-black tree"
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* with 64-bit integer keys. The search operation will return the
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* highest node <= the key; only search and insert are supported, but
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* additional standard llrbtree operations can be coded up at will.
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*
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* See http://www.cs.princeton.edu/~rs/talks/LLRB/RedBlack.pdf for
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* information about left-leaning red-black trees.
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*
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* The "threaded" part means that left and right pointers that would
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* otherwise be NULL are pointers to the in-order predecessor or
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* successor node. The only pointers that are NULL are the very left-
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* and rightmost, for which no corresponding side node exists.
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*
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* This, among other things, allows for efficient predecessor and
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* successor operations without requiring dedicated space for a parent
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* pointer.
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*
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* This implementation is robust for identical key values; such keys
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* will not have their insertion order preserved, and after insertion
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* of unrelated keys a lookup may return a different node for the
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* duplicated key, but the prev/next operations will always enumerate
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* all entries.
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*
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* The NULL pointers at the end are considered predecessor/successor
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* pointers, so if the corresponding flags are clear it is always safe
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* to access the pointed-to object without an explicit NULL pointer
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* check.
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*/
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#include "rbtree.h"
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#include "nasmlib.h"
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struct rbtree *rb_search(const struct rbtree *tree, uint64_t key)
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{
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const struct rbtree *best = NULL;
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if (tree) {
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while (true) {
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if (tree->key > key) {
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if (tree->m.flags & RBTREE_NODE_PRED)
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break;
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tree = tree->m.left;
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} else {
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best = tree;
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if (tree->key == key || (tree->m.flags & RBTREE_NODE_SUCC))
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break;
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tree = tree->m.right;
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}
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}
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}
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return (struct rbtree *)best;
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}
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struct rbtree *rb_search_exact(const struct rbtree *tree, uint64_t key)
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{
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struct rbtree *rv;
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rv = rb_search(tree, key);
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return (rv && rv->key == key) ? rv : NULL;
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}
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/* Reds two left in a row? */
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static inline bool is_red_left_left(struct rbtree *h)
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{
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return !(h->m.flags & RBTREE_NODE_PRED) &&
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!(h->m.left->m.flags & (RBTREE_NODE_BLACK|RBTREE_NODE_PRED)) &&
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!(h->m.left->m.left->m.flags & RBTREE_NODE_BLACK);
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}
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/* Node to the right is red? */
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static inline bool is_red_right(struct rbtree *h)
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{
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return !(h->m.flags & RBTREE_NODE_SUCC) &&
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!(h->m.right->m.flags & RBTREE_NODE_BLACK);
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}
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/* Both the left and right hand nodes are red? */
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static inline bool is_red_both(struct rbtree *h)
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{
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return !(h->m.flags & (RBTREE_NODE_PRED|RBTREE_NODE_SUCC))
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&& !(h->m.left->m.flags & h->m.right->m.flags & RBTREE_NODE_BLACK);
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}
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static inline struct rbtree *rotate_left(struct rbtree *h)
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{
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struct rbtree *x = h->m.right;
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enum rbtree_node_flags hf = h->m.flags;
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enum rbtree_node_flags xf = x->m.flags;
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if (xf & RBTREE_NODE_PRED) {
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h->m.right = x;
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h->m.flags = (hf & RBTREE_NODE_PRED) | RBTREE_NODE_SUCC;
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} else {
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h->m.right = x->m.left;
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h->m.flags = hf & RBTREE_NODE_PRED;
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}
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x->m.flags = (hf & RBTREE_NODE_BLACK) | (xf & RBTREE_NODE_SUCC);
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x->m.left = h;
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return x;
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}
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static inline struct rbtree *rotate_right(struct rbtree *h)
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{
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struct rbtree *x = h->m.left;
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enum rbtree_node_flags hf = h->m.flags;
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enum rbtree_node_flags xf = x->m.flags;
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if (xf & RBTREE_NODE_SUCC) {
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h->m.left = x;
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h->m.flags = (hf & RBTREE_NODE_SUCC) | RBTREE_NODE_PRED;
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} else {
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h->m.left = x->m.right;
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h->m.flags = hf & RBTREE_NODE_SUCC;
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}
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x->m.flags = (hf & RBTREE_NODE_BLACK) | (xf & RBTREE_NODE_PRED);
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x->m.right = h;
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return x;
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}
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static inline void color_flip(struct rbtree *h)
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{
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h->m.flags ^= RBTREE_NODE_BLACK;
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h->m.left->m.flags ^= RBTREE_NODE_BLACK;
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h->m.right->m.flags ^= RBTREE_NODE_BLACK;
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}
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static struct rbtree *
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_rb_insert(struct rbtree *tree, struct rbtree *node);
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struct rbtree *rb_insert(struct rbtree *tree, struct rbtree *node)
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{
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/* Initialize node as if it was the sole member of the tree */
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nasm_zero(node->m);
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node->m.flags = RBTREE_NODE_PRED|RBTREE_NODE_SUCC;
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if (unlikely(!tree))
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return node;
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return _rb_insert(tree, node);
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}
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static struct rbtree *
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_rb_insert(struct rbtree *tree, struct rbtree *node)
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{
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/* Recursive part of the algorithm */
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/* Red on both sides? */
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if (is_red_both(tree))
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color_flip(tree);
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if (node->key < tree->key) {
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node->m.right = tree; /* Potential successor */
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if (tree->m.flags & RBTREE_NODE_PRED) {
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node->m.left = tree->m.left;
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tree->m.flags &= ~RBTREE_NODE_PRED;
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tree->m.left = node;
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} else {
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tree->m.left = _rb_insert(tree->m.left, node);
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}
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} else {
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node->m.left = tree; /* Potential predecessor */
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if (tree->m.flags & RBTREE_NODE_SUCC) {
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node->m.right = tree->m.right;
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tree->m.flags &= ~RBTREE_NODE_SUCC;
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tree->m.right = node;
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} else {
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tree->m.right = _rb_insert(tree->m.right, node);
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}
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}
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if (is_red_right(tree))
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tree = rotate_left(tree);
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if (is_red_left_left(tree))
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tree = rotate_right(tree);
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return tree;
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}
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struct rbtree *rb_first(const struct rbtree *tree)
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{
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if (unlikely(!tree))
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return NULL;
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while (!(tree->m.flags & RBTREE_NODE_PRED))
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tree = tree->m.left;
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return (struct rbtree *)tree;
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}
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struct rbtree *rb_last(const struct rbtree *tree)
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{
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if (unlikely(!tree))
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return NULL;
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while (!(tree->m.flags & RBTREE_NODE_SUCC))
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tree = tree->m.right;
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return (struct rbtree *)tree;
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}
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struct rbtree *rb_prev(const struct rbtree *node)
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{
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struct rbtree *np = node->m.left;
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if (node->m.flags & RBTREE_NODE_PRED)
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return np;
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else
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return rb_last(np);
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}
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struct rbtree *rb_next(const struct rbtree *node)
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{
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struct rbtree *np = node->m.right;
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if (node->m.flags & RBTREE_NODE_SUCC)
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return np;
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else
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return rb_first(np);
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}
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