There was a logic error in #7815 which made
Variant.hash_compare() == Variant.hash_compare() always true.
In an attempt to short-circuit the NaN check I made an (in hindsight) obvious
error: 10 == 12 || is_nan(10) == is_nan(12)
This will be true for all inputs, except for the NaN, not-NaN case. The macro
has been updated to now generate:
(10 == 12) || (is_nan(10) && is_nan(10))
so:
(10 == 12) || (is_nan(10) && is_nan(12)) = false
False or (False and False) is False
(10 == 10) || (is_nan(10) && is_nan(10)) = true
True or (False and False) is True
(Nan == 10) || (is_nan(NaN) && is_nan(10)) = false
False or (True and False) is False
(Nan == Nan) || (is_nan(NaN) && is_nan(NaN)) = true
False or (True and True) is True
Which is correct for all cases.
This bug was triggered because the hash function for floating point numbers
can very easily generate collisions for the tested Vector3(). I've also added
an extra hashing step to the float hash function to make this less likely to
occur.
This fixes#8081 and probably many more random weirdness.
8ff6e53833