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Fix: String::format Variant to String conversion

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Previosly String::format used variant.get_construct_string() to convert
the passed Variants to Strings. This however did not match the expected
printing behavior of some datatypes: Strings for example turned out
escaped.

This fix replaces the call to get_construct_string() with a simple
conversion. This makes String::format consistent with "%s" % "sth" and
formated Variants turn out like printed as expected.
This commit is contained in:
David Sichma 2018-10-19 21:53:37 +02:00
parent 0d8284d3d4
commit 62848f94ee
1 changed files with 5 additions and 9 deletions
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14
core/ustring.cpp
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@ -2774,16 +2774,13 @@ String String::format(const Variant &values, String placeholder) const {
if (value_arr.size() == 2) {
Variant v_key = value_arr[0];
String key;
key = v_key.get_construct_string();
String key = v_key;
if (key.left(1) == "\"" && key.right(key.length() - 1) == "\"") {
key = key.substr(1, key.length() - 2);
}
Variant v_val = value_arr[1];
String val;
val = v_val.get_construct_string();
String val = v_val;
if (val.left(1) == "\"" && val.right(val.length() - 1) == "\"") {
val = val.substr(1, val.length() - 2);
@ -2795,8 +2792,7 @@ String String::format(const Variant &values, String placeholder) const {
}
} else { //Array structure ["RobotGuy","Logis","rookie"]
Variant v_val = values_arr[i];
String val;
val = v_val.get_construct_string();
String val = v_val;
if (val.left(1) == "\"" && val.right(val.length() - 1) == "\"") {
val = val.substr(1, val.length() - 2);
@ -2815,8 +2811,8 @@ String String::format(const Variant &values, String placeholder) const {
d.get_key_list(&keys);
for (List<Variant>::Element *E = keys.front(); E; E = E->next()) {
String key = E->get().get_construct_string();
String val = d[E->get()].get_construct_string();
String key = E->get();
String val = d[E->get()];
if (key.left(1) == "\"" && key.right(key.length() - 1) == "\"") {
key = key.substr(1, key.length() - 2);