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Interpret numeric parameter correctly.

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This commit is contained in:
Ulrich Drepper 2000-12-27 23:29:08 +00:00
parent f77b82e81b
commit 22fea1a1b6
1 changed files with 26 additions and 38 deletions
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64
sysdeps/alpha/alphaev67/strncat.S
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@ -38,57 +38,45 @@ ENTRY(strncat)
#endif #endif
.prologue 1 .prologue 1
mov $16, $0 # set up return value mov a0, v0 # set up return value
beq $18, $zerocount # U : beq a2, $zerocount # U :
/* Find the end of the string. */ /* Find the end of the string. */
ldq_u $1, 0($16) # L : load first quadword ($16 may be misaligned) ldq_u t0, 0(a0) # L : load first quadword (a0 may be misaligned)
lda $2, -1($31) # E : lda t1, -1 # E :
insqh $2, $0, $2 # U : insqh t1, v0, t1 # U :
andnot $16, 7, $16 # E : andnot a0, 7, a0 # E :
nop # E : nop # E :
or $2, $1, $1 # E : or t1, t0, t0 # E :
nop # E : nop # E :
nop # E : nop # E :
cmpbge $31, $1, $2 # E : bits set iff byte == 0 cmpbge zero, t0, t1 # E : bits set iff byte == 0
bne $2, $found # U : bne t1, $found # U :
$loop: ldq $1, 8($16) # L : $loop: ldq t0, 8(a0) # L :
addq $16, 8, $16 # E : addq a0, 8, a0 # E :
cmpbge $31, $1, $2 # E : cmpbge zero, t0, t1 # E :
beq $2, $loop # U : beq t1, $loop # U :
$found: cttz $2, $3 # U0 : $found: cttz t1, t2 # U0 :
addq $16, $3, $16 # E : addq a0, t2, a0 # E :
jsr $23, __stxncpy # L0 :/* Now do the append. */ jsr t9, __stxncpy # L0 : Now do the append.
/* Worry about the null termination. */ /* Worry about the null termination. */
zapnot $1, $27, $2 # U : was last byte a null? cttz t10, t2 # U0: byte offset of end-of-count.
cmplt $27, $24, $5 # E : did we fill the buffer completely? nop # E :
bne $2, 0f # U : zapnot t0, t8, t1 # U : was last byte a null?
nop # E :
bne t1, 0f # U :
nop # E :
nop # E :
ret # L0 : ret # L0 :
0: or $5, $18, $2 # E : 0: addq t2, a0, a0 # E : address of end-of-count
nop stb zero, 1(a0) # L :
bne $2, 2f # U :
and $24, 0x80, $3 # E : no zero next byte
nop # E :
bne $3, 1f # U :
/* Here there are bytes left in the current word. Clear one. */
addq $24, $24, $24 # E : end-of-count bit <<= 1
nop # E :
2: zap $1, $24, $1 # U :
nop # E :
stq_u $1, 0($16) # L :
ret # L0 :
1: /* Here we must clear the first byte of the next DST word */
stb $31, 8($16) # L :
nop # E :
nop # E : nop # E :
ret # L0 : ret # L0 :