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Interpret numeric parameter correctly.
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@ -38,57 +38,45 @@ ENTRY(strncat)
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#endif
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.prologue 1
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mov $16, $0 # set up return value
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beq $18, $zerocount # U :
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mov a0, v0 # set up return value
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beq a2, $zerocount # U :
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/* Find the end of the string. */
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ldq_u $1, 0($16) # L : load first quadword ($16 may be misaligned)
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lda $2, -1($31) # E :
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ldq_u t0, 0(a0) # L : load first quadword (a0 may be misaligned)
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lda t1, -1 # E :
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insqh $2, $0, $2 # U :
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andnot $16, 7, $16 # E :
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insqh t1, v0, t1 # U :
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andnot a0, 7, a0 # E :
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nop # E :
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or $2, $1, $1 # E :
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or t1, t0, t0 # E :
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nop # E :
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nop # E :
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cmpbge $31, $1, $2 # E : bits set iff byte == 0
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bne $2, $found # U :
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cmpbge zero, t0, t1 # E : bits set iff byte == 0
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bne t1, $found # U :
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$loop: ldq $1, 8($16) # L :
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addq $16, 8, $16 # E :
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cmpbge $31, $1, $2 # E :
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beq $2, $loop # U :
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$loop: ldq t0, 8(a0) # L :
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addq a0, 8, a0 # E :
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cmpbge zero, t0, t1 # E :
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beq t1, $loop # U :
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$found: cttz $2, $3 # U0 :
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addq $16, $3, $16 # E :
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jsr $23, __stxncpy # L0 :/* Now do the append. */
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$found: cttz t1, t2 # U0 :
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addq a0, t2, a0 # E :
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jsr t9, __stxncpy # L0 : Now do the append.
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/* Worry about the null termination. */
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zapnot $1, $27, $2 # U : was last byte a null?
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cmplt $27, $24, $5 # E : did we fill the buffer completely?
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bne $2, 0f # U :
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cttz t10, t2 # U0: byte offset of end-of-count.
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nop # E :
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zapnot t0, t8, t1 # U : was last byte a null?
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nop # E :
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bne t1, 0f # U :
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nop # E :
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nop # E :
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ret # L0 :
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0: or $5, $18, $2 # E :
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nop
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bne $2, 2f # U :
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and $24, 0x80, $3 # E : no zero next byte
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nop # E :
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bne $3, 1f # U :
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/* Here there are bytes left in the current word. Clear one. */
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addq $24, $24, $24 # E : end-of-count bit <<= 1
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nop # E :
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2: zap $1, $24, $1 # U :
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nop # E :
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stq_u $1, 0($16) # L :
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ret # L0 :
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1: /* Here we must clear the first byte of the next DST word */
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stb $31, 8($16) # L :
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nop # E :
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0: addq t2, a0, a0 # E : address of end-of-count
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stb zero, 1(a0) # L :
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nop # E :
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ret # L0 :
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