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* libjava.lang/Primes.java: New file. * libjava.lang/Primes.out: New file. From-SVN: r28613
214 lines
6.5 KiB
Java
214 lines
6.5 KiB
Java
// Primes.java
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/** Copyright 1998
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* Roedy Green
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* Canadian Mind Products
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* 5317 Barker Avenue
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* Burnaby, BC Canada V5H 2N6
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* tel: (604) 435-3016
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* mailto:roedy@mindprod.com
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* http://mindprod.com
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*/
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// May be freely distributed for any purpose but military
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import java.util.BitSet;
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/**
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* @author Roedy Green
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* @version 1.10 1998 November 10
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* Calculate primes using Eratostheses Sieve.
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* Tell if a given number is prime.
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* Find a prime just below a given number.
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* Find a prime just above a given number.
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*/
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/*
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* version 1.1 1998 November 10 - new address and phone.
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*/
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class Primes
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{
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/**
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* constructors
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*/
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Primes()
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{
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ensureCapacity(1000);
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}
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/**
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* @param capacity - largest number you will be asking if prime.
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* If give too small a number, it will automatically grow by
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* recomputing the sieve array.
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*/
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Primes (int capacity)
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{
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ensureCapacity(capacity);
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}
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/**
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* @param candidate - is this a prime?
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*/
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public boolean isPrime(int candidate)
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{
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ensureCapacity(candidate);
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if (candidate < 3) return candidate != 0;
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if (candidate % 2 == 0 ) return false;
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return !b.get(candidate/2);
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}
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/**
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* @return first prime higher than candidate
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*/
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public int above(int candidate)
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{
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do
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{
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// see what we can find in the existing sieve
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for (int i=candidate+1; i<= sieveCapacity; i++)
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{
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if (isPrime(i)) return i;
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}
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// Keep building ever bigger sieves till we succeed.
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// The next prime P' is between P+2 and P^2 - 2.
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// However that is a rather pessimistic upper bound.
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// Ideally some theorem would tell us how big we need to build
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// to find one.
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ensureCapacity(Math.max(candidate*2, sieveCapacity*2));
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} // end do
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while (true);
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} // end above
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/**
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* @param return first prime less than candidate
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*/
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public int below (int candidate)
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{
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for (candidate--; candidate > 0; candidate--)
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{
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if (isPrime(candidate)) return candidate;
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}
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// candidate was 1 or 0 or -ve
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return 0;
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}
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/**
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* calc all primes in the range 1..n,
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* not the first n primes.
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* @param n, highest candidate, not necessarily prime.
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* @return list of primes 1..n in an array
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*/
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public final int[] getPrimes(int n)
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{
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// calculate the primes
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ensureCapacity(n);
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// pass 1: count primes
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int countPrimes = 0;
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for (int i = 0; i <= n; i++)
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{
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if (isPrime(i)) countPrimes++;
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}
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// pass 2: construct array of primes
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int [] primes = new int[countPrimes];
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countPrimes = 0;
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for (int i = 0; i <= n; i++)
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{
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if (isPrime(i)) primes[countPrimes++] = i;
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}
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return primes;
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} // end getPrimes
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/**
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* calculate the sieve, bit map of all primes 0..n
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* @param n highest number evalutated by the sieve, not necessarily prime.
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*/
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private final void sieve ( int n )
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{
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// Presume BitSet b set is big enough for our purposes.
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// Presume all even numbers are already marked composite, effectively.
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// Presume all odd numbers are already marked prime (0 in bit map).
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int last = (int)(Math.sqrt(n))+1;
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for (int candidate = 3; candidate <= last; candidate += 2)
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{
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// only look at odd numbers
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if (!b.get(candidate/2) /* if candidate is prime */)
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{
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// Our candidate is prime.
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// Only bother to mark multiples of primes. Others already done.
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// no need to mark even multiples, already done
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int incr = candidate*2;
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for ( int multiple = candidate + incr; multiple < n; multiple += incr)
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{
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b.set(multiple/2); // mark multiple as composite
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} // end for multiple
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} // end if
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} // end for candidate
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// at this point our sieve b is correct, except for 0..2
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} // end sieve
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/**
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* Ensure have a sieve to tackle primes as big as n.
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* If we don't allocate a sieve big enough and calculate it.
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* @param n - ensure sieve big enough to evaluate n for primality.
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*/
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private void ensureCapacity (int n)
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{
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if ( n > sieveCapacity )
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{
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b = new BitSet((n+1)/2);
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// starts out all 0, presume all numbers prime
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sieveCapacity = n;
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sieve(n);
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}
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// otherwise existing sieve is fine
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} // end ensureCapacity
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private int sieveCapacity;
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// biggest number we have computed in our sieve.
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// our BitSet array is indexed 0..N (odd only)
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private BitSet b; /* true for each odd number if is composite */
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/**
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* Demonstrate and test the methods
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*/
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public static void main (String[] args)
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{
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// print primes 1..101
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Primes calc = new Primes(106);
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int[] primes = calc.getPrimes(101);
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for (int i=0; i<primes.length; i++)
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{
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System.out.println(primes[i]);
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}
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// demonstrate isPrime, above, below
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System.out.println(calc.isPrime(149));
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System.out.println(calc.below(149));
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System.out.println(calc.above(149));
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// print all the primes just greater than powers of 2
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calc = new Primes(10000000);
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for (int pow=8; pow < 10000000; pow*=2)
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System.out.println(calc.above(pow));
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// Validate that isPrime works by comparing it with brute force
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for (int i=3; i<=151; i++)
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{
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boolean prime = true;
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for (int j=2; j<i; j++)
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{
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if (i % j == 0 )
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{
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prime = false;
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break;
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}
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} // end for j
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if ( calc.isPrime(i) != prime ) System.out.println(i + " oops");
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} // end for i
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} // end main
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} // end Primes
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