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* sort.c (sort_pointers): Fix endianness bugs.
From-SVN: r33368
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@ -1,5 +1,7 @@
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2000-04-23 Mark Mitchell <mark@codesourcery.com>
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* sort.c (sort_pointers): Fix endianness bugs.
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* sort.c: New file.
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* Makefile.in (CFILES): Add sort.c
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(REQUIRED_OFILES): Add sort.o.
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@ -29,9 +29,8 @@ Boston, MA 02111-1307, USA. */
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#include <stdlib.h>
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#endif
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/* POINTERSP and WORKP both point to arrays of N pointers. When
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this function returns POINTERSP will point to a sorted version of
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the original array pointed to by POINTERSP. */
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/* POINTERS and WORK are both arrays of N pointers. When this
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function returns POINTERS will be sorted in ascending order. */
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void sort_pointers (n, pointers, work)
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size_t n;
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@ -63,8 +62,11 @@ void sort_pointers (n, pointers, work)
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abort ();
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/* Figure out the endianness of the machine. */
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for (i = 0; i < sizeof (size_t); ++i)
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((char *)&j)[i] = i;
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for (i = 0, j = 0; i < sizeof (size_t); ++i)
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{
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j *= (UCHAR_MAX + 1);
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j += i;
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}
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big_endian_p = (((char *)&j)[0] == 0);
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/* Move through the pointer values from least significant to most
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@ -91,8 +93,8 @@ void sort_pointers (n, pointers, work)
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/* Compute the address of the appropriate digit in the first and
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one-past-the-end elements of the array. On a little-endian
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machine, the least-significant digit is closest to the front. */
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bias = ((digit_t *) pointers) + i;
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top = ((digit_t *) (pointers + n)) + i;
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bias = ((digit_t *) pointers) + j;
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top = ((digit_t *) (pointers + n)) + j;
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/* Count how many there are of each value. At the end of this
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loop, COUNT[K] will contain the number of pointers whose Ith
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@ -109,7 +111,7 @@ void sort_pointers (n, pointers, work)
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/* Now, drop the pointers into their correct locations. */
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for (pointerp = pointers + n - 1; pointerp >= pointers; --pointerp)
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work[--count[((digit_t *) pointerp)[i]]] = *pointerp;
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work[--count[((digit_t *) pointerp)[j]]] = *pointerp;
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/* Swap WORK and POINTERS so that POINTERS contains the sorted
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array. */
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