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c++: Don't try to parse a function declaration as deduction guide [PR97663]

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While these function declarations have NULL decl_specifiers->type,
they have still type specifiers specified from which the default int
in the return type is added, so we shouldn't try to parse those as
deduction guides.

2020-11-03  Jakub Jelinek  <jakub@redhat.com>

	PR c++/97663
	* parser.c (cp_parser_init_declarator): Don't try to parse
	C++17 deduction guides if there are any type specifiers even when
	type is NULL.

	* g++.dg/cpp1z/class-deduction75.C: New test.
This commit is contained in:
Jakub Jelinek 2020-11-03 21:42:51 +01:00
parent 9f925f3b19
commit 875225301e
2 changed files with 16 additions and 0 deletions
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1
gcc/cp/parser.c
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@ -20790,6 +20790,7 @@ cp_parser_init_declarator (cp_parser* parser,
{
/* Handle C++17 deduction guides. */
if (!decl_specifiers->type
&& !decl_specifiers->any_type_specifiers_p
&& ctor_dtor_or_conv_p <= 0
&& cxx_dialect >= cxx17)
{

15
gcc/testsuite/g++.dg/cpp1z/class-deduction75.C Normal file
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@ -0,0 +1,15 @@
// PR c++/97663
template <class T> struct foo {};
template <class T> struct bar {};
template <class T> struct baz {};
template <class T> struct qux {};
template <class T> struct corge {};
namespace N {
unsigned foo ();
signed bar ();
long baz ();
long long qux ();
short corge ();
}