c++: Deducing type from initializer_list<auto> [PR93107]

In this testcase we weren't able to deduce b's type:

  template<typename T> void Task() { }
  auto b = { &Task<int> };

because resolve_nondeduced_context doesn't iterate on the {}'s elements.
So make sure to look into {} too.  We don't need to handle nested {}
here.

We could either tweak resolve_nondeduced_context to handle CONSTRUCTORs
or add a _ctor version, but then resolve_nondeduced_context_or_error
would need some changes too -- it'd have to check the result of a call
to r_n_c for each element.

gcc/cp/ChangeLog:

	PR c++/93107
	* pt.c (do_auto_deduction): Call resolve_nondeduced_context for
	the elements of a { } list.

gcc/testsuite/ChangeLog:

	PR c++/93107
	* g++.dg/cpp0x/initlist-deduce3.C: New test.
This commit is contained in:
Marek Polacek 2020-10-16 11:00:12 -04:00
parent 79991e2348
commit 6fb7e3c291
2 changed files with 29 additions and 1 deletions

View File

@ -29241,7 +29241,13 @@ do_auto_deduction (tree type, tree init, tree auto_node,
if (type == error_mark_node)
return error_mark_node;
init = resolve_nondeduced_context (init, complain);
if (BRACE_ENCLOSED_INITIALIZER_P (init))
/* We don't recurse here because we can't deduce from a nested
initializer_list. */
for (constructor_elt &elt : *CONSTRUCTOR_ELTS (init))
elt.value = resolve_nondeduced_context (elt.value, complain);
else
init = resolve_nondeduced_context (init, complain);
if (context == adc_decomp_type
&& auto_node == type

View File

@ -0,0 +1,22 @@
// PR c++/93107
// { dg-do compile { target c++11 } }
using size_t = decltype(sizeof 0);
namespace std {
template<typename T> struct initializer_list {
const T *ptr;
size_t n;
initializer_list(const T*, size_t);
};
}
template<typename T>
void Task() {}
auto a = &Task<int>;
auto b = { &Task<int> };
auto e{ &Task<int> };
auto f = { &Task<int>, &Task<int> };
std::initializer_list<void(*)()> c = { &Task<int> };
auto d = { static_cast<void(*)()>(&Task<int>) };