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compiler: If unary & does not escape, the var does not escape.

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If we have a unary & that takes the address of a variable, do
not force the variable to escape if the unary & does not
escape.

From-SVN: r223100
This commit is contained in:
Ian Lance Taylor 2015-05-12 22:13:01 +00:00
parent 7e269fe875
commit 38109dbe01
1 changed files with 6 additions and 1 deletions
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7
gcc/go/gofrontend/expressions.cc
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@ -3668,7 +3668,12 @@ Unary_expression::do_flatten(Gogo* gogo, Named_object*,
if (this->op_ == OPERATOR_AND)
{
if (this->expr_->var_expression() != NULL)
// If this->escapes_ is false at this point, then it was set to
// false by an explicit call to set_does_not_escape, and the
// value does not escape. If this->escapes_ is true, we may be
// able to set it to false if taking the address of a variable
// that does not escape.
if (this->escapes_ && this->expr_->var_expression() != NULL)
{
Named_object* var = this->expr_->var_expression()->named_object();
if (var->is_variable())