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315 lines
13 KiB
Plaintext
315 lines
13 KiB
Plaintext
namespace Eigen {
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/** \page TutorialAdvancedLinearAlgebra Tutorial 3/4 - Advanced linear algebra
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\ingroup Tutorial
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<div class="eimainmenu">\ref index "Overview"
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| \ref TutorialCore "Core features"
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| \ref TutorialGeometry "Geometry"
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| \b Advanced \b linear \b algebra
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| \ref TutorialSparse "Sparse matrix"
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</div>
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This tutorial chapter explains how you can use Eigen to tackle various problems involving matrices:
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solving systems of linear equations, finding eigenvalues and eigenvectors, and so on.
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\b Table \b of \b contents
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- \ref TutorialAdvSolvers
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- \ref TutorialAdvLU
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- \ref TutorialAdvCholesky
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- \ref TutorialAdvQR
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- \ref TutorialAdvEigenProblems
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\section TutorialAdvSolvers Solving linear problems
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This part of the tutorial focuses on solving systems of linear equations. Such systems can be
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written in the form \f$ A \mathbf{x} = \mathbf{b} \f$, where both \f$ A \f$ and \f$ \mathbf{b} \f$
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are known, and \f$ \mathbf{x} \f$ is the unknown. Moreover, \f$ A \f$ is assumed to be a square
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matrix.
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The equation \f$ A \mathbf{x} = \mathbf{b} \f$ has a unique solution if \f$ A \f$ is invertible. If
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the matrix is not invertible, then the equation may have no or infinitely many solutions. All
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solvers assume that \f$ A \f$ is invertible, unless noted otherwise.
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Eigen offers various algorithms to this problem. The choice of algorithm mainly depends on the
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nature of the matrix \f$ A \f$, such as its shape, size and numerical properties.
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- The \ref TutorialAdvSolvers_LU "LU decomposition" (with partial pivoting) is a general-purpose
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algorithm which works for most problems.
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- Use the \ref TutorialAdvSolvers_Cholesky "Cholesky decomposition" if the matrix \f$ A \f$ is
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positive definite.
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- Use a special \ref TutorialAdvSolvers_Triangular "triangular solver" if the matrix \f$ A \f$ is
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upper or lower triangular.
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- Use of the \ref TutorialAdvSolvers_Inverse "matrix inverse" is not recommended in general, but
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may be appropriate in special cases, for instance if you want to solve several systems with the
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same matrix \f$ A \f$ and that matrix is small.
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- \ref TutorialAdvSolvers_Misc "Other solvers" (%LU decomposition with full pivoting, the singular
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value decomposition) are provided for special cases, such as when \f$ A \f$ is not invertible.
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The methods described here can be used whenever an expression involve the product of an inverse
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matrix with a vector or another matrix: \f$ A^{-1} \mathbf{v} \f$ or \f$ A^{-1} B \f$.
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\subsection TutorialAdvSolvers_LU LU decomposition (with partial pivoting)
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This is a general-purpose algorithm which performs well in most cases (provided the matrix \f$ A \f$
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is invertible), so if you are unsure about which algorithm to pick, choose this. The method proceeds
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in two steps. First, the %LU decomposition with partial pivoting is computed using the
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MatrixBase::partialLu() function. This yields an object of the class PartialLU. Then, the
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PartialLU::solve() method is called to compute a solution.
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As an example, suppose we want to solve the following system of linear equations:
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\f[ \begin{aligned}
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x + 2y + 3z &= 3 \\
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4x + 5y + 6z &= 3 \\
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7x + 8y + 10z &= 4.
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\end{aligned} \f]
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The following program solves this system:
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<table class="tutorial_code"><tr><td>
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\include Tutorial_PartialLU_solve.cpp
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</td><td>
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output: \include Tutorial_PartialLU_solve.out
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</td></tr></table>
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There are many situations in which we want to solve the same system of equations with different
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right-hand sides. One possibility is to put the right-hand sides as columns in a matrix \f$ B \f$
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and then solve the equation \f$ A X = B \f$. For instance, suppose that we want to solve the same
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system as before, but now we also need the solution of the same equations with 1 on the right-hand
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side. The following code computes the required solutions:
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<table class="tutorial_code"><tr><td>
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\include Tutorial_solve_multiple_rhs.cpp
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</td><td>
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output: \include Tutorial_solve_multiple_rhs.out
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</td></tr></table>
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However, this is not always possible. Often, you only know the right-hand side of the second
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problem, and whether you want to solve it at all, after you solved the first problem. In such a
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case, it's best to save the %LU decomposition and reuse it to solve the second problem. This is
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worth the effort because computing the %LU decomposition is much more expensive than using it to
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solve the equation. Here is some code to illustrate the procedure. It uses the constructor
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PartialLU::PartialLU(const MatrixType&) to compute the %LU decomposition.
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<table class="tutorial_code"><tr><td>
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\include Tutorial_solve_reuse_decomposition.cpp
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</td><td>
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output: \include Tutorial_solve_reuse_decomposition.out
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</td></tr></table>
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\b Warning: All this code presumes that the matrix \f$ A \f$ is invertible, so that the system
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\f$ A \mathbf{x} = \mathbf{b} \f$ has a unique solution. If the matrix \f$ A \f$ is not invertible,
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then the system \f$ A \mathbf{x} = \mathbf{b} \f$ has either zero or infinitely many solutions. In
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both cases, PartialLU::solve() will give nonsense results. For example, suppose that we want to
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solve the same system as above, but with the 10 in the last equation replaced by 9. Then the system
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of equations is inconsistent: adding the first and the third equation gives \f$ 8x + 10y + 12z = 7 \f$,
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which implies \f$ 4x + 5y + 6z = 3\frac12 \f$, in contradiction with the second equation. If we try
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to solve this inconsistent system with Eigen, we find:
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<table class="tutorial_code"><tr><td>
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\include Tutorial_solve_singular.cpp
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</td><td>
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output: \include Tutorial_solve_singular.out
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</td></tr></table>
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The %LU decomposition with \b full pivoting (class LU) and the singular value decomposition (class
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SVD) may be helpful in this case, as explained in the section \ref TutorialAdvSolvers_Misc below.
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\sa LU_Module, MatrixBase::partialLu(), PartialLU::solve(), class PartialLU.
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\subsection TutorialAdvSolvers_Cholesky Cholesky decomposition
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If the matrix \f$ A \f$ is \b symmetric \b positive \b definite, then the best method is to use a
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Cholesky decomposition: it is both faster and more accurate than the %LU decomposition. Such
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positive definite matrices often arise when solving overdetermined problems. These are linear
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systems \f$ A \mathbf{x} = \mathbf{b} \f$ in which the matrix \f$ A \f$ has more rows than columns,
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so that there are more equations than unknowns. Typically, there is no vector \f$ \mathbf{x} \f$
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which satisfies all the equation. Instead, we look for the least-square solution, that is, the
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vector \f$ \mathbf{x} \f$ for which \f$ \| A \mathbf{x} - \mathbf{b} \|_2 \f$ is minimal. You can
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find this vector by solving the equation \f$ A^T \! A \mathbf{x} = A^T \mathbf{b} \f$. If the matrix
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\f$ A \f$ has full rank, then \f$ A^T \! A \f$ is positive definite and thus you can use the
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Cholesky decomposition to solve this system and find the least-square solution to the original
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system \f$ A \mathbf{x} = \mathbf{b} \f$.
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Eigen offers two different Cholesky decompositions: the LLT class provides a \f$ LL^T \f$
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decomposition where L is a lower triangular matrix, and the LDLT class provides a \f$ LDL^T \f$
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decomposition where L is lower triangular with unit diagonal and D is a diagonal matrix. The latter
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includes pivoting and avoids square roots; this makes the %LDLT decomposition slightly more stable
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than the %LLT decomposition. The LDLT class is able to handle both positive- and negative-definite
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matrices, but not indefinite matrices.
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The API is the same as when using the %LU decomposition.
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\code
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#include <Eigen/Cholesky>
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MatrixXf D = MatrixXf::Random(8,4);
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MatrixXf A = D.transpose() * D;
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VectorXf b = A * VectorXf::Random(4);
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VectorXf x;
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A.llt().solve(b,&x); // using a LLT factorization
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A.ldlt().solve(b,&x); // using a LDLT factorization
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\endcode
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The LLT and LDLT classes also provide an \em in \em place API for the case where the value of the
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right hand-side \f$ b \f$ is not needed anymore.
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\code
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A.llt().solveInPlace(b);
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\endcode
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This code replaces the vector \f$ b \f$ by the result \f$ x \f$.
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As before, you can reuse the factorization if you have to solve the same linear problem with
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different right-hand sides, e.g.:
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\code
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// ...
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LLT<MatrixXf> lltOfA(A);
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lltOfA.solveInPlace(b0);
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lltOfA.solveInPlace(b1);
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// ...
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\endcode
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\sa Cholesky_Module, MatrixBase::llt(), MatrixBase::ldlt(), LLT::solve(), LLT::solveInPlace(),
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LDLT::solve(), LDLT::solveInPlace(), class LLT, class LDLT.
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\subsection TutorialAdvSolvers_Triangular Triangular solver
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If the matrix \f$ A \f$ is triangular (upper or lower) and invertible (the coefficients of the
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diagonal are all not zero), then the problem can be solved directly using the TriangularView
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class. This is much faster than using an %LU or Cholesky decomposition (in fact, the triangular
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solver is used when you solve a system using the %LU or Cholesky decomposition). Here is an example:
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<table class="tutorial_code"><tr><td>
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\include Tutorial_solve_triangular.cpp
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</td><td>
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output: \include Tutorial_solve_triangular.out
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</td></tr></table>
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The MatrixBase::triangularView() function constructs an object of the class TriangularView, and
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TriangularView::solve() then solves the system. There is also an \e in \e place variant:
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<table class="tutorial_code"><tr><td>
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\include Tutorial_solve_triangular_inplace.cpp
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</td><td>
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output: \include Tutorial_solve_triangular_inplace.out
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</td></tr></table>
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\sa MatrixBase::triangularView(), TriangularView::solve(), TriangularView::solveInPlace(),
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TriangularView class.
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\subsection TutorialAdvSolvers_Inverse Direct inversion (for small matrices)
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The solution of the system \f$ A \mathbf{x} = \mathbf{b} \f$ is given by \f$ \mathbf{x} = A^{-1}
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\mathbf{b} \f$. This suggests the following approach for solving the system: compute the matrix
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inverse and multiply that with the right-hand side. This is often not a good approach: using the %LU
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decomposition with partial pivoting yields a more accurate algorithm that is usually just as fast or
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even faster. However, using the matrix inverse can be faster if the matrix \f$ A \f$ is small
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(≤4) and fixed size, though numerical stability problems may still remain. Here is an example of
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how you would write this in Eigen:
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<table class="tutorial_code"><tr><td>
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\include Tutorial_solve_matrix_inverse.cpp
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</td><td>
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output: \include Tutorial_solve_matrix_inverse.out
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</td></tr></table>
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Note that the function inverse() is defined in the \ref LU_Module.
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\sa MatrixBase::inverse().
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\subsection TutorialAdvSolvers_Misc Other solvers (for singular matrices and special cases)
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Finally, Eigen also offer solvers based on a singular value decomposition (%SVD) or the %LU
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decomposition with full pivoting. These have the same API as the solvers based on the %LU
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decomposition with partial pivoting (PartialLU).
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The solver based on the %SVD uses the class SVD. It can handle singular matrices. Here is an example
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of its use:
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\code
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#include <Eigen/SVD>
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// ...
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MatrixXf A = MatrixXf::Random(20,20);
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VectorXf b = VectorXf::Random(20);
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VectorXf x;
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A.svd().solve(b, &x);
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SVD<MatrixXf> svdOfA(A);
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svdOfA.solve(b, &x);
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\endcode
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%LU decomposition with full pivoting has better numerical stability than %LU decomposition with
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partial pivoting. It is defined in the class LU. The solver can also handle singular matrices.
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\code
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#include <Eigen/LU>
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// ...
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MatrixXf A = MatrixXf::Random(20,20);
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VectorXf b = VectorXf::Random(20);
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VectorXf x;
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A.lu().solve(b, &x);
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LU<MatrixXf> luOfA(A);
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luOfA.solve(b, &x);
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\endcode
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See the section \ref TutorialAdvLU below.
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\sa class SVD, SVD::solve(), SVD_Module, class LU, LU::solve(), LU_Module.
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<a href="#" class="top">top</a>\section TutorialAdvLU LU
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Eigen provides a rank-revealing LU decomposition with full pivoting, which has very good numerical stability.
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You can obtain the LU decomposition of a matrix by calling \link MatrixBase::lu() lu() \endlink, which is the easiest way if you're going to use the LU decomposition only once, as in
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\code
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#include <Eigen/LU>
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MatrixXf A = MatrixXf::Random(20,20);
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VectorXf b = VectorXf::Random(20);
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VectorXf x;
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A.lu().solve(b, &x);
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\endcode
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Alternatively, you can construct a named LU decomposition, which allows you to reuse it for more than one operation:
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\code
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#include <Eigen/LU>
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MatrixXf A = MatrixXf::Random(20,20);
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Eigen::LU<MatrixXf> lu(A);
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cout << "The rank of A is" << lu.rank() << endl;
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if(lu.isInvertible()) {
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cout << "A is invertible, its inverse is:" << endl << lu.inverse() << endl;
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}
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else {
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cout << "Here's a matrix whose columns form a basis of the kernel a.k.a. nullspace of A:"
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<< endl << lu.kernel() << endl;
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}
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\endcode
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\sa LU_Module, LU::solve(), class LU
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<a href="#" class="top">top</a>\section TutorialAdvCholesky Cholesky
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todo
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\sa Cholesky_Module, LLT::solve(), LLT::solveInPlace(), LDLT::solve(), LDLT::solveInPlace(), class LLT, class LDLT
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<a href="#" class="top">top</a>\section TutorialAdvQR QR
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todo
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\sa QR_Module, class QR
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<a href="#" class="top">top</a>\section TutorialAdvEigenProblems Eigen value problems
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todo
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\sa class SelfAdjointEigenSolver, class EigenSolver
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*/
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}
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