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Fix triangularView versus triangularPart.

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Gael Guennebaud 2016-02-12 17:09:28 +01:00
parent 4252af6897
commit 6eff3e5185
1 changed files with 4 additions and 4 deletions
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8
doc/TemplateKeyword.dox
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@ -73,13 +73,13 @@ for operator<".
The reason that the \c template keyword is necessary in the last example has to do with the rules for how
templates are supposed to be compiled in C++. The compiler has to check the code for correct syntax at the
point where the template is defined, without knowing the actual value of the template arguments (\c Derived1
and \c Derived2 in the example). That means that the compiler cannot know that <tt>dst.triangularPart</tt> is
and \c Derived2 in the example). That means that the compiler cannot know that <tt>dst.triangularView</tt> is
a member template and that the following &lt; symbol is part of the delimiter for the template
parameter. Another possibility would be that <tt>dst.triangularPart</tt> is a member variable with the &lt;
parameter. Another possibility would be that <tt>dst.triangularView</tt> is a member variable with the &lt;
symbol refering to the <tt>operator&lt;()</tt> function. In fact, the compiler should choose the second
possibility, according to the standard. If <tt>dst.triangularPart</tt> is a member template (as in our case),
possibility, according to the standard. If <tt>dst.triangularView</tt> is a member template (as in our case),
the programmer should specify this explicitly with the \c template keyword and write <tt>dst.template
triangularPart</tt>.
triangularView</tt>.
The precise rules are rather complicated, but ignoring some subtleties we can summarize them as follows:
- A <em>dependent name</em> is name that depends (directly or indirectly) on a template parameter. In the