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adapt to change: lu() now gives partial piv LU, here we want fullPivLu()
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@ -3,7 +3,7 @@ A << 1,2,3, 4,5,6, 7,8,10;
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Matrix<float,3,2> B;
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B << 3,1, 3,1, 4,1;
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Matrix<float,3,2> X;
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X = A.lu().solve(B);
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X = A.fullPivLu().solve(B);
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cout << "The solution with right-hand side (3,3,4) is:" << endl;
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cout << X.col(0) << endl;
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cout << "The solution with right-hand side (1,1,1) is:" << endl;
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