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added URL to the exception paragraph in the GPL FAQ
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@ -10,13 +10,14 @@ can lead to for end users.
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I am not a lawyer and this is not legal advice!
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I am not a lawyer and this is not legal advice!
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One common dilemma is that GPL[*]-licensed code is not allowed to be linked
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One common dilemma is that GPL[1]-licensed code is not allowed to be linked
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with code licensed under the Original BSD license (with the announcement
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with code licensed under the Original BSD license (with the announcement
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clause, unless there's a specified exception in the GPL-licensed module). You
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clause, unless there's a specified exception in the GPL-licensed module). You
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may still build your own copies that use them all, but distributing them as
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may still build your own copies that use them all, but distributing them as
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binaries would be to violate the GPL license. This particular problem was
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binaries would be to violate the GPL license - unless you accompany your
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addressed when the Modified BSD license was created, which does not have the
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license with an exception[2]. This particular problem was addressed when the
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annoncement clause that collides with GPL.
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Modified BSD license was created, which does not have the annoncement clause
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that collides with GPL.
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libcurl http://curl.haxx.se/docs/copyright.html
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libcurl http://curl.haxx.se/docs/copyright.html
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@ -80,4 +81,6 @@ OpenLDAP http://www.openldap.org/software/release/license.html
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linked with libcurl in an app.
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linked with libcurl in an app.
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[*] = GPL - GNU General Public License: http://www.gnu.org/licenses/gpl.html
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[1] = GPL - GNU General Public License: http://www.gnu.org/licenses/gpl.html
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[2] = http://www.fsf.org/licenses/gpl-faq.html#GPLIncompatibleLibs details on
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how to write such an exception to the GPL
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