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While looking at a different Ada problem, I found that printing a record containing a VLA did not work properly. I tracked the problem down to dwarf2_evaluate_property trying, and failing, to compare two types that differed only in qualifiers. This patch changes dwarf2_evaluate_property to ignore qualifiers when comparing types. Tested on x86-64 Fedora 29. gdb/ChangeLog 2019-05-08 Tom Tromey <tromey@adacore.com> * dwarf2loc.c (dwarf2_evaluate_property) <PROP_ADDR_OFFSET>: Compare main types. gdb/testsuite/ChangeLog 2019-05-08 Tom Tromey <tromey@adacore.com> * gdb.ada/vla.exp: New file. * gdb.ada/vla/vla.adb: New file.
39 lines
1.4 KiB
Plaintext
39 lines
1.4 KiB
Plaintext
# Copyright 2019 Free Software Foundation, Inc.
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#
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 3 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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load_lib "ada.exp"
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if { [skip_ada_tests] } { return -1 }
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standard_ada_testfile vla
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if {[gdb_compile_ada "${srcfile}" "${binfile}" executable {debug}] != ""} {
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return -1
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}
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clean_restart ${testfile}
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set bp_location [gdb_get_line_number "Set breakpoint here" ${testdir}/vla.adb]
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runto "vla.adb:$bp_location"
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gdb_test "print r00" \
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"= \\(l1 => 0, l2 => 0, i1 => 1, i2 => 2, i3 => 3, a1 => \\(\\), a2 => \\(\\)\\)"
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gdb_test "print r01" \
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"= \\(l1 => 0, l2 => 1, i1 => 1, i2 => 2, i3 => 3, a1 => \\(\\), a2 => \\(20\\)\\)"
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gdb_test "print r10" \
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"= \\(l1 => 1, l2 => 0, i1 => 1, i2 => 2, i3 => 3, a1 => \\(10\\), a2 => \\(\\)\\)"
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gdb_test "print r22" \
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"= \\(l1 => 2, l2 => 2, i1 => 1, i2 => 2, i3 => 3, a1 => \\(10, 10\\), a2 => \\(20, 20\\)\\)"
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