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1b90b13906
... so that we don't need to do it manually, and potentially forget. For example, this allows to do: my_flags flags; ... flags |= some_flag; gdb/ChangeLog: * common/enum-flags.h (enum_flags::enum_flags): Initialize m_enum_value to 0 in default constructor.
226 lines
6.1 KiB
C++
226 lines
6.1 KiB
C++
/* Copyright (C) 2015-2017 Free Software Foundation, Inc.
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This file is part of GDB.
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This program is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program. If not, see <http://www.gnu.org/licenses/>. */
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#ifndef COMMON_ENUM_FLAGS_H
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#define COMMON_ENUM_FLAGS_H
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/* Type-safe wrapper for enum flags. enum flags are enums where the
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values are bits that are meant to be ORed together.
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This allows writing code like the below, while with raw enums this
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would fail to compile without casts to enum type at the assignments
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to 'f':
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enum some_flag
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{
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flag_val1 = 1 << 1,
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flag_val2 = 1 << 2,
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flag_val3 = 1 << 3,
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flag_val4 = 1 << 4,
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};
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DEF_ENUM_FLAGS_TYPE(enum some_flag, some_flags)
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some_flags f = flag_val1 | flag_val2;
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f |= flag_val3;
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It's also possible to assign literal zero to an enum flags variable
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(meaning, no flags), dispensing adding an awkward explicit "no
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value" value to the enumeration. For example:
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some_flags f = 0;
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f |= flag_val3 | flag_val4;
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Note that literal integers other than zero fail to compile:
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some_flags f = 1; // error
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*/
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#ifdef __cplusplus
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/* Traits type used to prevent the global operator overloads from
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instantiating for non-flag enums. */
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template<typename T> struct enum_flags_type {};
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/* Use this to mark an enum as flags enum. It defines FLAGS as
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enum_flags wrapper class for ENUM, and enables the global operator
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overloads for ENUM. */
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#define DEF_ENUM_FLAGS_TYPE(enum_type, flags_type) \
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typedef enum_flags<enum_type> flags_type; \
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template<> \
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struct enum_flags_type<enum_type> \
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{ \
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typedef enum_flags<enum_type> type; \
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}
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/* Until we can rely on std::underlying type being universally
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available (C++11), roll our own for enums. */
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template<int size, bool sign> class integer_for_size { typedef void type; };
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template<> struct integer_for_size<1, 0> { typedef uint8_t type; };
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template<> struct integer_for_size<2, 0> { typedef uint16_t type; };
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template<> struct integer_for_size<4, 0> { typedef uint32_t type; };
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template<> struct integer_for_size<8, 0> { typedef uint64_t type; };
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template<> struct integer_for_size<1, 1> { typedef int8_t type; };
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template<> struct integer_for_size<2, 1> { typedef int16_t type; };
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template<> struct integer_for_size<4, 1> { typedef int32_t type; };
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template<> struct integer_for_size<8, 1> { typedef int64_t type; };
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template<typename T>
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struct enum_underlying_type
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{
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typedef typename
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integer_for_size<sizeof (T), static_cast<bool>(T (-1) < T (0))>::type
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type;
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};
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template <typename E>
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class enum_flags
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{
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public:
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typedef E enum_type;
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typedef typename enum_underlying_type<enum_type>::type underlying_type;
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private:
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/* Private type used to support initializing flag types with zero:
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foo_flags f = 0;
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but not other integers:
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foo_flags f = 1;
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The way this works is that we define an implicit constructor that
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takes a pointer to this private type. Since nothing can
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instantiate an object of this type, the only possible pointer to
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pass to the constructor is the NULL pointer, or, zero. */
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struct zero_type;
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underlying_type
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underlying_value () const
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{
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return m_enum_value;
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}
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public:
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/* Allow default construction. */
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enum_flags ()
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: m_enum_value ((enum_type) 0)
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{}
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enum_flags (const enum_flags &other)
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: m_enum_value (other.m_enum_value)
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{}
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enum_flags &operator= (const enum_flags &other)
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{
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m_enum_value = other.m_enum_value;
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return *this;
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}
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/* If you get an error saying these two overloads are ambiguous,
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then you tried to mix values of different enum types. */
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enum_flags (enum_type e)
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: m_enum_value (e)
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{}
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enum_flags (struct enum_flags::zero_type *zero)
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: m_enum_value ((enum_type) 0)
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{}
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enum_flags &operator&= (enum_type e)
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{
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m_enum_value = (enum_type) (underlying_value () & e);
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return *this;
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}
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enum_flags &operator|= (enum_type e)
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{
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m_enum_value = (enum_type) (underlying_value () | e);
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return *this;
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}
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enum_flags &operator^= (enum_type e)
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{
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m_enum_value = (enum_type) (underlying_value () ^ e);
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return *this;
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}
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operator enum_type () const
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{
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return m_enum_value;
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}
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enum_flags operator& (enum_type e) const
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{
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return (enum_type) (underlying_value () & e);
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}
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enum_flags operator| (enum_type e) const
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{
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return (enum_type) (underlying_value () | e);
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}
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enum_flags operator^ (enum_type e) const
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{
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return (enum_type) (underlying_value () ^ e);
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}
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enum_flags operator~ () const
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{
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return (enum_type) ~underlying_value ();
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}
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private:
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/* Stored as enum_type because GDB knows to print the bit flags
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neatly if the enum values look like bit flags. */
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enum_type m_enum_value;
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};
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/* Global operator overloads. */
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template <typename enum_type>
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typename enum_flags_type<enum_type>::type
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operator& (enum_type e1, enum_type e2)
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{
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return enum_flags<enum_type> (e1) & e2;
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}
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template <typename enum_type>
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typename enum_flags_type<enum_type>::type
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operator| (enum_type e1, enum_type e2)
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{
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return enum_flags<enum_type> (e1) | e2;
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}
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template <typename enum_type>
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typename enum_flags_type<enum_type>::type
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operator^ (enum_type e1, enum_type e2)
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{
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return enum_flags<enum_type> (e1) ^ e2;
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}
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template <typename enum_type>
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typename enum_flags_type<enum_type>::type
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operator~ (enum_type e)
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{
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return ~enum_flags<enum_type> (e);
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}
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#else /* __cplusplus */
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/* In C, the flags type is just a typedef for the enum type. */
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#define DEF_ENUM_FLAGS_TYPE(enum_type, flags_type) \
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typedef enum_type flags_type
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#endif /* __cplusplus */
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#endif /* COMMON_ENUM_FLAGS_H */
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