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type alignment: Use type_length_units
The type alignment value is returned in 8-bit-bytes instead of target memory addressable units. For example, on a target with 16-bit-bytes where sizeof(int) == 1 (one addressable unit), alignof(int) currently returns 2. After, this patch, it returns 1. gdb/ChangeLog: * arch-utils.c (default_type_align): Use type_length_units. * gdbtypes.c (type_align): Use type_length_units.
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@ -1,3 +1,8 @@
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2018-06-14 Simon Marchi <simon.marchi@ericsson.com>
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* arch-utils.c (default_type_align): Use type_length_units.
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* gdbtypes.c (type_align): Use type_length_units.
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2018-06-14 Philippe Waroquiers <philippe.waroquiers@skynet.be>
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* cli/cli-script.c (_initialize_cli_script): Fix online documentation
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@ -994,7 +994,7 @@ default_in_indirect_branch_thunk (gdbarch *gdbarch, CORE_ADDR pc)
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ULONGEST
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default_type_align (struct gdbarch *gdbarch, struct type *type)
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{
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return TYPE_LENGTH (check_typedef (type));
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return type_length_units (check_typedef (type));
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}
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void
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@ -3072,7 +3072,7 @@ type_align (struct type *type)
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case TYPE_CODE_METHODPTR:
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case TYPE_CODE_MEMBERPTR:
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align = TYPE_LENGTH (type);
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align = type_length_units (type);
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break;
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case TYPE_CODE_VOID:
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