autoconf/config/mdate-sh
Akim Demaille 18ca9ab3ec * config/config.guess, config/config.sub, config/elisp-comp,
* config/install-sh, config/mdate-sh, config/mkinstalldirs,
* config/texinfo.tex, doc/standards.texi: Update from masters.
2003-05-22 07:37:43 +00:00

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#!/bin/sh
# Get modification time of a file or directory and pretty-print it.
# Copyright (C) 1995, 1996, 1997, 2003 Free Software Foundation, Inc.
# written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2, or (at your option)
# any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software Foundation,
# Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
# As a special exception to the GNU General Public License, if you
# distribute this file as part of a program that contains a
# configuration script generated by Autoconf, you may include it under
# the same distribution terms that you use for the rest of that program.
# Prevent date giving response in another language.
LANG=C
export LANG
LC_ALL=C
export LC_ALL
LC_TIME=C
export LC_TIME
save_arg1="$1"
# Find out how to get the extended ls output of a file or directory.
if ls -L /dev/null 1>/dev/null 2>&1; then
ls_command='ls -L -l -d'
else
ls_command='ls -l -d'
fi
# A `ls -l' line looks as follows on OS/2.
# drwxrwx--- 0 Aug 11 2001 foo
# This differs from Unix, which adds ownership information.
# drwxrwx--- 2 root root 4096 Aug 11 2001 foo
#
# To find the date, we split the line on spaces and iterate on words
# until we find a month. This cannot work with files whose owner is a
# user named `Jan', or `Feb', etc. However, it's unlikely that `/'
# will be owned by a user whose name is a month. So we first look at
# the extended ls output of the root directory to decide how many
# words should be skipped to get the date.
# On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
set - x`$ls_command /`
# Find which argument is the month.
month=
command=
until test $month
do
shift
# Add another shift to the command.
command="$command shift;"
case $1 in
Jan) month=January; nummonth=1;;
Feb) month=February; nummonth=2;;
Mar) month=March; nummonth=3;;
Apr) month=April; nummonth=4;;
May) month=May; nummonth=5;;
Jun) month=June; nummonth=6;;
Jul) month=July; nummonth=7;;
Aug) month=August; nummonth=8;;
Sep) month=September; nummonth=9;;
Oct) month=October; nummonth=10;;
Nov) month=November; nummonth=11;;
Dec) month=December; nummonth=12;;
esac
done
# Get the extended ls output of the file or directory.
set - x`eval "$ls_command \"\$save_arg1\""`
# Remove all preceding arguments
eval $command
# Get the month. Next argument is day, followed by the year or time.
case $1 in
Jan) month=January; nummonth=1;;
Feb) month=February; nummonth=2;;
Mar) month=March; nummonth=3;;
Apr) month=April; nummonth=4;;
May) month=May; nummonth=5;;
Jun) month=June; nummonth=6;;
Jul) month=July; nummonth=7;;
Aug) month=August; nummonth=8;;
Sep) month=September; nummonth=9;;
Oct) month=October; nummonth=10;;
Nov) month=November; nummonth=11;;
Dec) month=December; nummonth=12;;
esac
day=$2
# Here we have to deal with the problem that the ls output gives either
# the time of day or the year.
case $3 in
*:*) set `date`; eval year=\$$#
case $2 in
Jan) nummonthtod=1;;
Feb) nummonthtod=2;;
Mar) nummonthtod=3;;
Apr) nummonthtod=4;;
May) nummonthtod=5;;
Jun) nummonthtod=6;;
Jul) nummonthtod=7;;
Aug) nummonthtod=8;;
Sep) nummonthtod=9;;
Oct) nummonthtod=10;;
Nov) nummonthtod=11;;
Dec) nummonthtod=12;;
esac
# For the first six month of the year the time notation can also
# be used for files modified in the last year.
if (expr $nummonth \> $nummonthtod) > /dev/null;
then
year=`expr $year - 1`
fi;;
*) year=$3;;
esac
# The result.
echo $day $month $year